## 1. Simplify x^2+3x - Mathway

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## 2. simplify (x^2-9)/(x^2-3x) - Symbolab

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## 3. How do you simplify (x^2+3x+2)/(x^2-1)? | Socratic

15 mei 2018 · \0/ here's our answer! Answer link · Kushagra. May 15, 2018.

(x²+3x+2)/(x²-1)=(x+2)/(x-1) (x²+3x+2)/(x²-1) =(cancel((x+1)) (x+2))/((x-1)cancel((x+1))) =(x+2)/(x-1) \0/ here's our answer!

## 4. Simplify (x^2-25)/(x^2-3x-10) | Mathway

Simplify the numerator. Tap for more steps... Step 1.1.

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## 5. Simplify the following products - 3x+1

Simplify each of the following products: (i) x 2 - 2 5 2 5 - x 2 - x 2 + 2 x (ii) x 2 + x - 2 x 2 - x + 2 (iii) x 3 - 3 x 2 - x x 2 - ...

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## 6. Solve x2-3x - Microsoft Math Solver

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## 7. How do you simplify (x^2 - 3x)/(2x - 6)? | Socratic

x2. Explanation: To simplify algebraic fractions you need to factorise the top and bottom as much as you can and then see what terms can be cancelled.

x/2 To simplify algebraic fractions you need to factorise the top and bottom as much as you can and then see what terms can be cancelled. At the top, we can take out a factor of x and at the bottom, we can take out a factor of 2. (x^2-3x)/(2x-6) =(x(x-3))/(2(x-3)) We can now cancel the x-3 from the top and bottom. =(xcancel((x-3)))/(2cancel((x-3))) =x/2

## 8. simplify expression (x^2 + 3x -9) | Wyzant Ask An Expert

31 dec 2013 · simplify expression (x^2 + 3x -9)

simplify expression (x^2 + 3x -9)

## 9. Simplify fully (x^2 + 3x)/(4x + 12) - MyTutor

Simplify fully (x^2 + 3x)/(4x + 12). You should begin by factorising the numerator and denominator, in order to determine what would go into both parts of the ...

You should begin by factorising the numerator and denominator, in order to determine what would go into both parts of the fraction.As you can see, x2 and 4x have ...

## 10. Simplify each of the following: i x2 3x+5 1/23x2 5x+7 ii [5 3x+2y 2x y ...

Simplify each of the following: i x2 3x+5 1/23x2 5x+7 ii [5 3x+2y 2x y] 3x 7y+9 iii 11/2x2y 9/4xy2+1/4xy 1/14y2x+1/15yx2+1/2xy iv 1/3y2 4/7y+11 1/7y 3+2y2 ...

See AlsoStacey Adin RossSimplify each of the following: i x2 3x+5 1/23x2 5x+7 ii [5 3x+2y 2x y] 3x 7y+9 iii 11/2x2y 9/4xy2+1/4xy 1/14y2x+1/15yx2+1/2xy iv 1/3y2 4/7y+11 1/7y 3+2y2 2/7y 2/3y2+2 v 1/2a2b2c+1/3ab2c 1/4abc2 1/5cb2a2+1/6cb2a 1/7c2ab+1/8ca2b.

## 11. Solve x^2-3x+2 | Microsoft Math Solver

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## 12. Simplify combining the like terms:x2 – 3x + y2 – x – 2y2 - Infinity Learn

The correct answer is x2 – 3x + y2 – x – 2y2= x2 + y2 – 2y2 – 3x – x= x2 – y2 – 4x.

## 13. Simplify (3x^2 + x -2)/(x^2 - 1) | MyTutor

2) (3x - 2)(x + 1) - the sum of the coefficients of x is 1.Therefore the factorised form is (3x - 2)(x + 1).The denominator can then be simplified very easily ...

First notice that no simplifications can be made to the problem without changing the form. We start by factorising the numerator. The highest power of x in this q...

## 14. Simplify each of the products: (x^3-3x^2-x)(x^2-3x+1) - Doubtnut

x^3-3x^2-x)(x^2-3x+1) =x(x^2-3x-1)(x^2-3x+1) =x[(x^2-3x)-1][(x^2-3x)+1] =x[(x^2-3x)^2-1^2] =x[x^4-6x^3+9x^2-1] =x^5-6x^4+9x^3-x.

(x^3-3x^2-x)(x^2-3x+1) =x(x^2-3x-1)(x^2-3x+1) =x[(x^2-3x)-1][(x^2-3x)+1] =x[(x^2-3x)^2-1^2] =x[x^4-6x^3+9x^2-1] =x^5-6x^4+9x^3-x

## 15. simplify (x^2-9)/(x^2-3x)

Detailed step by step solution for simplify (x^2-9)/(x^2-3x)

## 16. Simplify: √(x2+3x+2)(x2+5x+6)x2(x2+4x+3 ...

9 jan 2020 · Click here:point_up_2:to get an answer to your question :writing_hand:simplify displaystyle sqrtfracleft x23x2 right left x25x6 right x2left ...

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## 17. Simplify - Math Central

Simplify: -3x (x2 + 2) (x + 2) (x + 3) I need help on these, learning how to set them up step by step to get a answer :) Thank you so much.

Hi Tiff,

## 18. Simplify x3 3 x2 xx2 3 x+1 - BYJU'S

... x3−3x2−x3+3x2−x ... Q. Simplify (x3- 3x2 - x)(x2- 3x + 1) · Q. (i) Simplify: (x3–2x2+3x ...

Simplify x3 3 x2 xx2 3 x+1

## 19. Given the function rule f(x) = x 2 - 3x + 2, what is the output of f(-2)?

30 jan 2024 · Just like arithmetic, algebra also contains all the different types of mathematical operators. Solution: In the given algebraic expression, we ...

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